## THE BAG OF NUTS.

(

Money Puzzles)

Three boys were given a bag of nuts as a Christmas present, and it was

agreed that they should be divided in proportion to their ages, which

together amounted to 171/2 years. Now the bag contained 770 nuts, and

as often as Herbert took four Robert took three, and as often as Herbert

took six Christopher took seven. The puzzle is to find out how many nuts

each had, and what were the boys' respective ages.

## Answer:

It will be found that when Herbert takes twelve, Robert and Christopher

will take nine and fourteen respectively, and that they will have

together taken thirty-five nuts. As 35 is contained in 770 twenty-two

times, we have merely to multiply 12, 9, and 14 by 22 to discover that

Herbert's share was 264, Robert's 198, and Christopher's 308. Then, as

the total of their ages is 171/2 years or half the sum of 12, 9, and 14,

their respective ages must be 6, 41/2, and 7 years.