## THE THREE GROUPS.

(

Money Puzzles)

There appeared in "Nouvelles Annales de Mathematiques" the following

puzzle as a modification of one of my "Canterbury Puzzles." Arrange the

nine digits in three groups of two, three, and four digits, so that the

first two numbers when multiplied together make the third. Thus, 12 x

483 = 5,796. I now also propose to include the cases where there are

one, four, and four digits, such as 4 x 1,738 = 6,952. Can you find all

the possible solutions in both cases?

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THE NINE COUNTERS.
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THE LOCKERS PUZZLE.