## THE NINE TREASURE BOXES.

(

Money Puzzles)

The following puzzle will illustrate the importance on occasions of

being able to fix the minimum and maximum limits of a required number.

This can very frequently be done. For example, it has not yet been

ascertained in how many different ways the knight's tour can be

performed on the chess board; but we know that it is fewer than the

number of combinations of 168 things taken 63 at a time and is greater

than 31,054,144--for the latter is the number of routes of a particular

type. Or, to take a more familiar case, if you ask a man how many coins

he has in his pocket, he may tell you that he has not the slightest

idea. But on further questioning you will get out of him some such

statement as the following: "Yes, I am positive that I have more than

three coins, and equally certain that there are not so many as

twenty-five." Now, the knowledge that a certain number lies between 2

and 12 in my puzzle will enable the solver to find the exact answer;

without that information there would be an infinite number of answers,

from which it would be impossible to select the correct one.

This is another puzzle received from my friend Don Manuel Rodriguez, the

cranky miser of New Castile. On New Year's Eve in 1879 he showed me nine

treasure boxes, and after informing me that every box contained a square

number of golden doubloons, and that the difference between the contents

of A and B was the same as between B and C, D and E, E and F, G and H,

or H and I, he requested me to tell him the number of coins in every one

of the boxes. At first I thought this was impossible, as there would be

an infinite number of different answers, but on consideration I found

that this was not the case. I discovered that while every box contained

coins, the contents of A, B, C increased in weight in alphabetical

order; so did D, E, F; and so did G, H, I; but D or E need not be

heavier than C, nor G or H heavier than F. It was also perfectly certain

that box A could not contain more than a dozen coins at the outside;

there might not be half that number, but I was positive that there were

not more than twelve. With this knowledge I was able to arrive at the

correct answer.

In short, we have to discover nine square numbers such that A, B, C; and

D, E, F; and G, H, I are three groups in arithmetical progression, the

common difference being the same in each group, and A being less than

12. How many doubloons were there in every one of the nine boxes?

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THE FIVE BRIGANDS.
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THE SPANISH MISER.